Engineering Board Exam Reviewer · Environmental Engineering · hard
Downstream of an outfall, a river has an initial ultimate BOD of 20 mg/L and an initial DO deficit of 1.0 mg/L. With k1 = 0.23/ day and k2 = 0.50/ day, at what time does the critical (minimum) DO occur?
- 2.65 days
- 2.88 days
- 3.70 days
- 5.30 days
Answer
A. 2.65 days
Solution
tc = [1/(k2 - k1)] (k2/k1)[1 - D0(k2 - k1)/(k1L0)] = (1/0.27) 2.174[1 - 0.27/4.6] = 2.65 days. (Critical deficit Dc = (k1/k2)L0e-k1tc = 5.00 mg/L.)
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