Engineering Board Exam Reviewer · Chemistry · medium
What is the percentage by mass of carbon in glucose ( C6H12O6)? (Use H = 1, C = 12, N = 14, O = 16, Na = 23, S = 32, Cl = 35.5, Ca = 40)
- 40%
- 6.67%
- 53.33%
- 25%
Answer
A. 40%
Solution
%C = 72/180 × 100 = 40%.
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