Engineering Board Exam Reviewer · Fluid Mechanics · hard
A hydraulic jump occurs in a wide rectangular channel. The depth before the jump is 0.4 m and the velocity is 6 m/s. What is the depth after the jump?
- 1.212 m
- 3.050 m
- 1.525 m
- 3.670 m
Answer
C. 1.525 m
Solution
Fr1 = 6/sqrt(9.81 × 0.4) = 3.029. y2 = (y1/2)[ 1 + 8Fr12 - 1] = 0.2[sqrt(1 + 8(9.174)) - 1] = 1.525 m.
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