Engineering Board Exam Reviewer · Thermodynamics · hard
A 0.5 m3 rigid tank contains air at 400 kPa and 300 K. The tank is heated and a relief valve releases air so that the remaining air is at 400 kPa and 350 K. How much air left the tank? (R = 0.287 kJ/kg· K)
- 0.332 kg
- 2.323 kg
- 1.991 kg
- 0.000 kg
Answer
A. 0.332 kg
Solution
m1 = PV/RT1 = 400(0.5)/[0.287(300)] = 2.323 kg; m2 = 400(0.5)/[0.287(350)] = 1.991 kg. m = 0.332 kg.
More Thermodynamics questions
- A gas mixture contains 2 kg of N2 (M = 28) and 1 kg of O2 (M = 32) at a total pressure of 300 kPa. What is the partial pressure of N2?
- Air consists of approximately 79% N2 and 21% O2 by mole. What is its apparent molecular weight? (M N2 = 28, M O2 = 32)
- How many kilomoles are there in 5 kg of carbon dioxide (M = 44 kg/kmol)?
- For air with R = 0.287 kJ/kg· K and k = 1.4, what is the value of cp?
- A gas has a specific gas constant of 0.2598 kJ/kg· K. What is its molecular weight?
- What is the specific gas constant of a gas with a molecular weight of 28 kg/kmol (e.g., nitrogen)?
- A gas in a rigid container is at 200 kPa and 300 K. If it is heated to 450 K, what is its final pressure?
- A gas occupies 2 m3 at 300 K. If it is heated at constant pressure to 450 K, what is its final volume?
- A gas occupies 3 m3 at 100 kPa. If it is compressed isothermally to 1 m3, what is its final pressure?
- What is the mass of air in a 2 m3 tank at 500 kPa absolute and 300 K? (R = 0.287 kJ/kg· K)