Engineering Board Exam Reviewer · Thermodynamics · medium

In a vapor-compression refrigeration cycle, h at evaporator exit = 390 kJ/kg, h at compressor exit = 425 kJ/kg, and h at condenser exit = 250 kJ/kg. What is the COP?

  1. 5.00
  2. 0.25
  3. 0.92
  4. 4.00

Answer

D. 4.00

Solution

RE = h1 - h4 = 390 - 250 = 140 kJ/kg (h4 = h3). W = h2 - h1 = 35 kJ/kg. COP = 140/35 = 4.00.

More Thermodynamics questions

  1. A cogeneration plant is one that:
  2. In a steam power plant, the component that converts the thermal energy of steam into mechanical work is the:
  3. Which of the following increases the thermal efficiency of a Rankine cycle?
  4. Air enters a compressor at 300 K and is compressed with a pressure ratio of 8. The actual exit temperature is 590 K. What is the…
  5. A steam power plant has a net work of 992 kJ per kg of steam. What is its steam rate?
  6. In an ideal Rankine cycle, the turbine inlet enthalpy is 3200 kJ/kg, turbine exit enthalpy is 2200 kJ/kg, the pump inlet enthalpy is 192…
  7. A regenerator in a gas turbine plant is most effective when:
  8. For an ideal Brayton cycle with minimum temperature 300 K and maximum temperature 1200 K, what pressure ratio gives the maximum net work?…
  9. For an ideal Brayton cycle with compressor inlet at 300 K, pressure ratio 8, and turbine inlet at 1300 K, what is the back work ratio? (k…
  10. An ideal Brayton cycle has a compressor inlet temperature of 300 K, a pressure ratio of 8, and a turbine inlet temperature of 1300 K. What…

All Thermodynamics Reviewer questions