Engineering Board Exam Reviewer · Engineering Mechanics · medium

Two concurrent forces, F1 = 105 N and F2 = 90 N, act on a particle with an angle of 40° between them. What is the magnitude of their resultant force?

  1. 195
  2. 15
  3. 176.84
  4. 183.31

Answer

D. 183.31

Solution

Using the law of cosines for two concurrent forces: R = sqrt(F1² + F22 + 2 · F1 · F2 · ( )) = sqrt(105² + 902 + 2(105)(90) (40°)) = 183.31 N.

More Engineering Mechanics questions

  1. A particle is held in equilibrium by three coplanar forces. Force F1 = 50 N acts at 0° from the positive x-axis, and Force F2 = 65 N acts…
  2. A force has a horizontal component of 40 N and a vertical component of 32 N. What is the magnitude of the resultant force?
  3. Two concurrent forces, F1 = 100 N and F2 = 83 N, act on a particle with an angle of 30° between them. What is the magnitude of their…
  4. Internal forces within a member are generally NOT shown in the free-body diagram of the whole structure because:
  5. For a ladder leaning against a smooth (frictionless) wall and resting on a rough floor, the free-body diagram of the ladder should include:
  6. In a free-body diagram, the weight of an object is typically represented as a force acting:
  7. When drawing an FBD of a two-body system where Body A rests on Body B, the contact force that Body B exerts on Body A should be:
  8. A fixed (built-in) support in a free-body diagram provides:
  9. A roller support in a free-body diagram provides a reaction:
  10. A pin (hinge) support in a free-body diagram provides reaction force(s) in:

All Engineering Mechanics Reviewer questions