Civil Service Exam Reviewer · Number Series · medium

What number(s) should complete the series: 4, 11, 25, 53, 109, ?

  1. 218
  2. 221
  3. 223
  4. 165

Answer

B. 221

Solution

Each term = previous × 2 + 3: 109 × 2 + 3 = 221.

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