Civil Service Exam Reviewer · Number Series · hard

What number(s) should complete the series: 8, 15, 29, 57, 113, ?

  1. 226
  2. 227
  3. 169
  4. 225

Answer

D. 225

Solution

Each term = previous × 2 − 1: 113 × 2 − 1 = 225.

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