Civil Service Exam Reviewer · Number Series · hard

What number(s) should complete the series: 217, 344, 513, 730, 1001, ?

  1. 1333
  2. 1272
  3. 1330
  4. 1332

Answer

D. 1332

Solution

The terms follow n³ + 1 for n = 6, 7, …; for n = 11: 1332.

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