Civil Service Exam Reviewer · Number Series · hard

What number(s) should complete the series: 9, 13, 21, 37, 69, ?

  1. 138
  2. 133
  3. 143
  4. 101

Answer

B. 133

Solution

Each term = previous × 2 − 5: 69 × 2 − 5 = 133.

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