Engineering Board Exam Reviewer · Uniform Gradient Series · easy
Find the equivalent uniform annual amount of a gradient series of P0, P1,000, P2,000, , P9,000 over years 1 to 10 at 6% interest.
- P4,500
- P4,022.01
- P9,000
- P29,602.32
Answer
B. P4,022.01
Solution
A=G(A/G,i,n)=1,000≤ft[ 1i-n/(1+i)n-1 ]=1,000(4.0220)=P4,022.01.
More Uniform Gradient Series questions
- Year-end payments are P0 in year 1 and then increase by P1,000 each year (0, 1,000, 2,000, 3,000, 4,000 for years 1 to 5). Find the…
- A deposit of P10,000 is made at the end of year 1 and each later deposit is 10% larger than the previous one, for 10 years. Find the…
- Year-end deposits start at P1,000 and increase by P100 each year for 10 years. Find the accumulated amount at the end of year 10 at 8%…
- Revenue is P20,000 at the end of year 1 and decreases by P2,000 each year for 5 years. Find the present worth at 10% interest.
- A cost is P10,000 at the end of year 1 and increases by 5% each year for 5 years. Find the present worth at 10% interest.
- Payments are P5,000 at the end of year 1 and increase by P1,000 each year for 6 years. Find the present worth at 12% interest.
- Maintenance cost is P2,000 at the end of year 1 and increases by P500 each year for 8 years. At 8% interest, find the equivalent uniform…