Engineering Board Exam Reviewer · Eigenvalues and Eigenvectors · medium
An eigenvector of bmatrix4&1\2&3 bmatrix corresponding to =5 is
- bmatrix1\-2 bmatrix
- bmatrix1\-1 bmatrix
- bmatrix2\1 bmatrix
- bmatrix1\1 bmatrix
Answer
D. bmatrix1\1 bmatrix
Solution
(A-5I)v= bmatrix-1&1\2&-2 bmatrixv=0 -v1+v2=0 v1=v2. So v= bmatrix1\1 bmatrix (and its multiples). The vector bmatrix1\-2 bmatrix belongs to =2.
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