Engineering Board Exam Reviewer · Fourier Series · hard
The half-range sine series of f(x)=x on (0,2) is bn π x/2. Find b2.
- -0.64
- 0.64
- 1.27
- -0.32
Answer
A. -0.64
Solution
bn=2/L 0Lf(x) π x/L,dx= 02x π x/2,dx=-4 nπ/nπ. For n=2: b2=-4/2π=- 2π -0.64.
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