Engineering Board Exam Reviewer · Permutations · hard
In how many ways can 5 men and 4 women be seated in a row so that no two women sit next to each other?
- 43,200
- 2,880
- 1,800
- 362,880
Answer
A. 43,200
Solution
Seat the men first: 5!=120 ways. This creates 6 gaps (including both ends). Place the 4 women in different gaps in 6P4=360 ways. Total =120×360=43,200.
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