Engineering Board Exam Reviewer · Parabolas · medium
Find the equation of the parabola with vertex (2,-1), a horizontal axis, and focus (5,-1).
- - 12 x + y2 + 2 y + 25 = 0
- 12 x + y2 + 2 y - 23 = 0
- x2 - 4 x - 12 y - 8 = 0
- - 12 x + y2 - 2 y + 25 = 0
Answer
A. - 12 x + y2 + 2 y + 25 = 0
Solution
p=5-2=3, so (y+1)2=4(3)(x-2)=12(x-2) y2+2y+1-12x+24=0 y2-12x+2y+25=0.
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