Engineering Board Exam Reviewer · Ellipses · medium

Find the foci of the ellipse (x-2)2/25+(y+1)2/9=1.

  1. (2,3) and (2,-5)
  2. (7,-1) and (-3,-1)
  3. (6,1) and (-2,1)
  4. (6,-1) and (-2,-1)

Answer

D. (6,-1) and (-2,-1)

Solution

The center is (2,-1), a=5, b=3, so c=sqrt(25-9)=4. The major axis is horizontal, so the foci are (2 4,-1), i.e. (6,-1) and (-2,-1).

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  1. Find the length of the latus rectum of the ellipse x2/36+y2/20=1.
  2. Find the equation of the ellipse with foci at ( 3,0) and a major axis of length 10.
  3. Find the eccentricity of the ellipse x2/25+y2/9=1.
  4. Find the foci of the ellipse x2/25+y2/9=1.
  5. Find the length of the major axis of the ellipse x2/25+y2/9=1.
  6. Find the distance from the center of the ellipse x2/25+y2/9=1 to each directrix.
  7. Find the area of the largest rectangle that can be inscribed in the ellipse x2/25+y2/9=1.
  8. Find the distance between the foci of the ellipse 4x2+9y2-16x+18y-11=0.
  9. Find the equation of the ellipse with center at the origin, vertices at ( 6,0) and a minor axis of length 8.
  10. A point on the ellipse 4x2+9y2=36 has x=2 and y>0. Find its y-coordinate.

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