Engineering Board Exam Reviewer · Conic Sections and Transformation of Axes · hard

The axes are rotated through 45°. Find the equation of xy=8 in terms of the new coordinates x' and y'.

  1. x'2+y'2=16
  2. x'2-y'2=8
  3. x'2-y'2=16
  4. x'2-y'2=32

Answer

C. x'2-y'2=16

Solution

Use x=x'-y'/ 2 and y=x'+y'/ 2. Then xy=x'2-y'2/2=8 x'2-y'2=16.

More Conic Sections and Transformation of Axes questions

  1. The coordinate axes are rotated counterclockwise through 90°. What are the new coordinates of the point (3,4)?
  2. The axes are translated so that the first-degree terms of x2+y2-4x+6y-3=0 disappear. What is the new origin?
  3. Through what acute angle must the axes be rotated to eliminate the xy-term of x2-2 3,xy+3y2+4x=0? Give the answer in degrees.
  4. Identify the graph of 2x2+xy+3y2-5=0.
  5. Identify the graph of x2+4xy+4y2+3x-2=0.
  6. Identify the graph of x2+y2-4x+6y=3.
  7. A conic has a focus at (2,0), the directrix x=8, and eccentricity 12. Find its equation.

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