Engineering Board Exam Reviewer · Properties of Triangles · hard

In triangle ABC, BC=14, CA=15 and AB=13. Find the distance from vertex A to the incenter.

  1. 4.64
  2. 9.29
  3. 12
  4. 8.06

Answer

D. 8.06

Solution

r=84/21=4. A=152+132-142/2(15)(13)=0.5077, so A=59.49°. The incenter lies on the bisector at AI=r/ (A/2)=4/ 29.74°=8.06.

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