Engineering Board Exam Reviewer · Solutions to Oblique Triangles · hard
A triangle has two sides of lengths 20 and 30 and an area of 150. Find the smallest possible length of the third side.
- 48.37
- 36.06
- 25
- 16.15
Answer
D. 16.15
Solution
12(20)(30) C=150 C= 12, so C=30° or 150°. c2=202+302-2(20)(30) C. For 30°: c=sqrt(260.77)=16.15; for 150°: c=48.37. The smallest is 16.15.
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