Engineering Board Exam Reviewer · Solutions to Oblique Triangles · medium
ME Board April 1997: An observer wishes to determine the height of a tower. He takes sights at the top of the tower from A and B, which are 50 feet apart, at the same elevation on a direct line with the tower. The vertical angle at point A is 30° and at point B is 40°. What is the height of the tower?
- 85.60 feet
- 92.54 feet
- 110.29 feet
- 143.97 feet
Answer
B. 92.54 feet
Solution
Let x = distance from B (nearer point) to the tower, h = height. 40°=h/x and 30°=h/x+50. Combining: h≤ft(1/ 30°-1/ 40° )=50, giving h 92.54 ft.
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