Engineering Board Exam Reviewer · Trigonometric Equations · medium
ECE Board November 1998: Solve for A for the given equation 2 A = 1- 2 A
- 45°, 125°, 225°, 335°
- 45°, 125°, 225°, 315°
- 45°, 135°, 225°, 315°
- 45°, 150°, 220°, 315°
Answer
C. 45°, 135°, 225°, 315°
Solution
2A=1- 2A 2 2A=1 A= 1/ 2 A=45°,135°,225°,315°.
More Trigonometric Equations questions
- CE Board May 1994: If conversed = 0.134, find the value of .
- ECE Board April 1993: Solve for in the following equation: 2 =
- CE Board November 1993: If 3A = 6B, then
- EE Board October 1996: Solve for x, if 3x = 5 x.
- EE Board October 1997: If x x + 2x = 1, what are the values of x?
- EE Board April 1997: Solve for G in (11G-16°) = (5G+26°).
- EE Board April 1992: Find the value of A between 270° and 360° if 2 2 A - A = 1.
- EE Board March 1998: If 2A = 1/ 13A, determine the angle A in degrees.