Engineering Board Exam Reviewer · Trigonometric Identities · hard
Simplify: ≤ft( ) + ≤ft(3 ) + ≤ft(5 ) ≤ft( ) + ≤ft(3 ) + ≤ft(5 )
- ≤ft(5 )
- ≤ft(3 )
- ≤ft( )
- ≤ft(3 ) ≤ft(5 )
Answer
B. ≤ft(3 )
Solution
Group 5 + =2 3 2 and 5 + =2 3 2 . The ratio is 3 (2 2 +1)/ 3 (2 2 +1)= 3 .
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