Engineering Board Exam Reviewer · Trigonometric Identities · medium

CE Board November 1993: Find the value of y in the given: y = (1+ 2 ) .

  3. 2
  4. 2

Answer

C. 2

Solution

y=(1+ 2 ) . Since 1+ 2 =2 2 : y=2 2 · / =2 = 2 .

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