Engineering Board Exam Reviewer · Homogeneous First-Order Equations · hard
Find the general solution of x,dy-y,dx=sqrt(x2+y2),dx for x>0.
- y + x2 + y2 = C x
- y - x2 + y2 = C x2
- y + x2 + y2 = C
- y + x2 + y2 = C x2
Answer
D. y + x2 + y2 = C x2
Solution
For x>0: dy/dx= yx+ sqrt(x2+y2)x. With y=vx: xv'=sqrt(1+v2) dvsqrt(1+v2)=dx/x -1v= x+c v+sqrt(1+v2)=Cx, i.e. y+sqrt(x2+y2)=Cx2.
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