Engineering Board Exam Reviewer · Bernoulli and Reducible Equations · hard
Find the general solution of dy/dx+y/x=xy3 for x>0.
1y2 = x2 ≤ft(C + 2 x )
1/y = x2 ≤ft(C - 2 x )
1y2 = x2 ≤ft(C - 2 x )
1y2 = x ≤ft(C - 2 x )
Answer
C. 1y2 = x2 ≤ft(C - 2 x )
Solution
Bernoulli with n=3. Let v=y-2: v'=-2y-3y'=-2x+2v/x, i.e. v'-2/xv=-2x. The integrating factor is x-2: d/dx≤ft(vx-2 )=- 2x vx-2=-2 x+C. So 1y2=x2(C-2 x).