Engineering Board Exam Reviewer · Exact Differential Equations · medium
Solve the exact differential equation (3x2+2y),dx+(2x+3y2),dy=0.
- x3+2xy+y3=C
- x3+xy+y3=C
- x2+2xy+y2=C
- x3-2xy+y3=C
Answer
A. x3+2xy+y3=C
Solution
Seeking F(x,y) with Fx=3x2+2y and Fy=2x+3y2 gives F=x3+2xy+y3+C1, so the solution is x3+2xy+y3=C.
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