Engineering Board Exam Reviewer · Variable Separable Equations · hard

Solve dy/dx=x2+1/y, given y(0)=2.

1. y2= 23x3+2x+4
2. y2=x3+x+4
3. y2= 23x3+2x
4. y= 23x3+2x+4

Answer

A. y2= 23x3+2x+4

Solution

y,dy=(x2+1),dx y2/2=x3/3+x+C1. Using y(0)=2: C1=2, so y2= 23x3+2x+4.

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