Engineering Board Exam Reviewer · Applications: Volume, Arc Length, Surface Area · easy

Find the length of the catenary y=5 x5 from x=0 to x=5.

  1. 5 ≤ft(1 ) 7.715
  2. -5 + 5 e 8.591
  3. ≤ft(1 ) 1.175
  4. 5 ≤ft(1 ) 5.876

Answer

D. 5 ≤ft(1 ) 5.876

Solution

y'= x5, so sqrt(1+y'2)= x5. L= 05 x5,dx=5 x5 |05=5 1 5.876.

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