Engineering Board Exam Reviewer · Logarithmic Differentiation · medium
Find y' if y=(x+1)2(x-3)3/x+2.
- ≤ft(x - 3 )3 ≤ft(x + 1 )2 ≤ft(1/x + 2 + 2/x + 1 + 3/x - 3 )x + 2
- - 1/x + 2 + 2/x + 1 + 3/x - 3
- ≤ft(x - 3 )3 ≤ft(x + 1 )2 ≤ft(4 x - 9 )x + 2
- ≤ft(x - 3 )3 ≤ft(x + 1 )2 ≤ft(- 1/x + 2 + 2/x + 1 + 3/x - 3 )x + 2
Answer
D. ≤ft(x - 3 )3 ≤ft(x + 1 )2 ≤ft(- 1/x + 2 + 2/x + 1 + 3/x - 3 )x + 2
Solution
y=2 (x+1)+3 (x-3)- (x+2). Differentiate: y'/y=2/x+1+3/x-3-1/x+2. Multiply by y.