Engineering Board Exam Reviewer · Tangent and Normal Lines · medium
Find the equation of the normal line to y= x at x=4.
- x-4y=-4
- 4x-y=14
- x+4y=12
- 4x+y=18
Answer
D. 4x+y=18
Solution
At x=4, y=2 and y'=1/2 x= 14. The normal slope is -4: y-2=-4(x-4) 4x+y=18. (The tangent would be x-4y=-4.)
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