Engineering Board Exam Reviewer · Derivatives of Hyperbolic Functions · medium
Differentiate y= (x2).
- 2x, sech2(x2)
- sech2(x2)
- 2x (x2)
- x, sech2(x2)
Answer
A. 2x, sech2(x2)
Solution
By the chain rule: y'= sech2(x2)·2x=2x, sech2(x2).
Engineering Board Exam Reviewer · Derivatives of Hyperbolic Functions · medium
A. 2x, sech2(x2)
By the chain rule: y'= sech2(x2)·2x=2x, sech2(x2).