Engineering Board Exam Reviewer · One-Sided Limits and Continuity · medium
Evaluate x 3+|x-3|/x2-9.
- 1/6
- -1/6
- 1/3
- 0
Answer
A. 1/6
Solution
For x>3, |x-3|=x-3. Then x-3/(x-3)(x+3)=1/x+3 16. (From the left the limit is - 16.)
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