Engineering Board Exam Reviewer · Motion Problems · medium
Train A leaves a station at 8:00 AM traveling at 60 km/h. Train B leaves the same station on the same track at 9:30 AM traveling at 90 km/h. At what time does B overtake A?
- 12:00 PM
- 1:30 PM
- 11:30 AM
- 12:30 PM
Answer
D. 12:30 PM
Solution
At 9:30 AM train A is 60(1.5)=90 km ahead. B closes the gap at 90-60=30 km/h, which takes 90/30=3 hours. So B overtakes A at 9:30+3:00=12:30 PM.
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