Engineering Board Exam Reviewer · Sequences and Series · medium
Find the sum of the first 12 terms of the geometric sequence 3, 6, 12,
- 12288
- 8190
- 12285
- 24573
Answer
C. 12285
Solution
Sn=a1(rn-1)/r-1= 3(212-1)2-1=3(4095)=12285.
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